- Strong acids and strong bases react to form neutral salts.
- Strong acids and weak bases react to form acidic salts.
- Weak acids and strong bases react to form basic salts.
- Weak acids and weak bases react to form either acidic or basic salts depending on the relative strengths of the acid and base.
- An ICE table is a useful tool to quantitatively determine the pH of a salt solution.
We’ve already seen that ions can act as acids or bases. For example, through the practice problems in the previous sections we've seen that NH4+ is a weak acid and CH3COO− is a weak base. Such ions are also associated with a counterion, which forms an ionic compound or salt. For example, CH3COO− may be paired with Na+ to form the salt CH3COONa. Soluble salts like these dissolve in water and dissociate into their anionic (e.g. CH3COO−) and cationic (e.g. Na+) components. If either of these ionic components are acidic or basic, they will react with water to affect the pH of the resulting solution, just as we saw for any weak acid or weak base. For example, since CH3COO− is a weak base and Na+ is neither an acid nor a base, dissolving CH3COONa in water results in a basic solution. The pH of such a solution can be determined using the same ICE table method as for any weak acid/base.
So how can we know whether any given salt would dissolve in water to give an acidic or basic solution? One simple approach is to consider the acid-base reaction that could have happened to form the salt (acid + base → salt) by following the steps below:
- Split the salt into its anionic and cationic components.
- Add H+ to the anion to form the acid that reacted to form the salt.
- If possible, remove H+ from the cation to form the base that reacted to form the salt. If there is no H+ to remove, instead consider the hydroxide (HO−) base as Xn+(−OH)n, where X is the cation.
- Consider the strength of the acid (step 2) and base (step 3) that reacted to make the salt to determine the qualitative pH of the salt solution.
- Strong acid + strong base → neutral salt
- Strong acid + weak base → acidic salt
- Weak acid + strong base → basic salt
- Weak acid + weak base → either acidic or basic salt depending on the relative strengths
Apply these steps to solve each of the examples below yourself before expanding to see the full solution.
View solution:
- This salt dissolves in water to form Na+ (the cation) and Cl− (the anion).
- Adding H+ to the anion, Cl−, gives the acid that reacts: HCl (a strong acid).
- The cation, Na+, has no H+ to remove so we consider the hydroxide base: NaOH (a strong base).
- A strong acid (HCl) and a strong base (NaOH) react to give a neutral salt, so NaCl dissolves to give a neutral solution.
Example 2: When KNO2 is dissolved in water, is the resulting solution acidic, basic or neutral?
View solution:
- This salt dissolves in water to form K+ (the cation) and NO2− (the anion).
- Adding H+ to the anion, NO2−, gives the acid that reacts: HNO2 (a weak acid).
- The cation, K+, has no H+ to remove so we consider the hydroxide base: KOH (a strong base).
- A weak acid (HNO2) and a strong base (KOH) react to give a basic salt, so KNO2 dissolves to give a basic solution.
Example 3: When CH3NH3Br is dissolved in water, is the resulting solution acidic, basic or neutral?
View solution:
- This salt dissolves in water to form CH3NH3+ (the cation) and Br− (the anion).
- Adding H+ to the anion, Br−, gives the acid that reacts: HBr (a strong acid).
- Removing H+ from the cation, CH3NH3+, gives the base that reacts: CH3NH2 (a weak base).
- A strong acid (HBr) and a weak base (CH3NH2) react to give an acidic salt, so CH3NH3Br dissolves to give an acidic solution.
An alternate approach:
While the above approach is straight forward, it may not be intuitively clear why it works. Let’s consider the four steps outlined above from a different perspective:
- Splitting the acid into its anion and cation components allows us to analyze each of these components separately to see how they each affect the pH.
  - Adding H+ to the anion forms the conjugate acid of the anion, which allows us to assess the strength of the anion as a base. If the resulting conjugate acid is weak, then the original anion is a weak base. If the resulting conjugate acid is strong, then the original anion does not act as a base.
For example, SO42− is a weak base (its conjugate acid, HSO4−, is weak) whereas Cl− does not act as a base (its conjugate acid, HCl, is strong).Why don’t anions act as bases when they have strong conjugate acids?
Strong acids, such as HCl, react essentially completely in water to form H3O+ and Cl−. The fact that essentially every molecule of HCl releases H+ in water (which forms H3O+) demonstrates that the remaining Cl− has a very low affinity for H+. That is, Cl− does not act as a base. Conversely, weak acids such as HSO4− only react partly in water, which demonstrates that their conjugate bases (e.g. SO42−) are weak since they have some affinity for H+. The stronger an acid is (i.e. the more it releases H+) the weaker its conjugate base will be (i.e. the less affinity the conjugate base has for H+).
- Removing H+ from the cation (if possible) forms the conjugate base of the cation, which allows us to assess the strength of the cation as an acid. If the resulting conjugate base is weak, then the original cation is a weak acid. If the resulting conjugate base is strong, then the original cation does not act as an acid. If H+ cannot be removed, then the species cannot act as an acid.
For example, NH4+ is a weak acid (its conjugate base, NH3, is weak) whereas Na+ does not act as an acid (there is no H+ to remove).
- To determine the overall pH of a salt solution, consider the acidity/basicity of the individual anion and cation components:
- If the anion does not act as a base and the cation does not act as an acid, then the resulting salt solution will be neutral.
- If the anion does not act as a base and the cation is a weak acid, then the resulting salt solution will be acidic.
- If the anion is a weak base and the cation does not act as an acid, then the resulting salt solution will be basic.
- If the anion is a weak base and the cation is a weak acid, then the pH of the resulting solution will depend on the relative strength and quantities of the acid vs base components.
What happens with polyprotic acids?
Polyprotic acids are those that, after releasing H+, can release another H+. For example, the strong acid H2SO4 is polyprotic because it can release H+ to form HSO4−, which can release another H+ to form SO42−. Consider a reaction between H2SO4, a strong acid, and NaOH, a strong base.
H2SO4 + NaOH → NaHSO4 + H2O
Notice that in the salt formed, HSO4−, our second approach would lead us to believe that Na+ is not acidic and HSO4− is not basic. Both of these conclusions are correct. However, using the analyses above would incorrectly lead us to conclude that NaHSO4, then, is a neutral salt. In fact, NaHSO4 would form an acidic solution if dissolved in water. The reason is that while HSO4− does not act as a base (since it’s the conjugate base of a strong acid), it can act as a weak acid because of the polyprotic nature of H2SO4 . When analyzing salts derived from polyatomic acids, be careful to consider the possibility of further reactions such as this.
The approaches above show how to qualitatively classify a solution as acidic, basic, or neutral. To calculate the pH of a salt solution quantitatively, use the same ICE table method introduced in the previous sections to assess how an acidic or basic cation or anion reacts with water to affect the pH. An example is given below.
View solution:
In example 2 above, we already determined that KNO2 dissolves to give K+ (a neutral cation which will not affect the pH) and NO2− (a weak base which will affect the pH). The fact that a Kb is given for NO2− in the question is another hint that this component of the salt is basic. To solve for the pH quantitatively, construct an ICE table for the reaction between the basic component, NO2−, and water:
Solve for x using the Kb equation and assume that x is small such that :
The value of x is less than 5% of our starting concentration, 2.0 M, so the assumption that was valid. Finally, we can solve for the pH using:
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